neoviper
Registered user
relate the drag figures to the power required to overcome them. If we add rolling resistance and air resistance together we get total drag in pounds. Power required is then calculated as:
Power (bhp) = Total drag x mph / 375
We could if required split the power into the amounts needed to overcome each drag separately. The equations would then become:
Power to overcome rolling resistance = weight x 0.013 x mph / 375
Power to overcome air drag = fA x Cd x 0.00256 x mph cubed / 375
Hopefully something of major importance should be clear from the above. We already know that it is air resistance that is the major element in this equation and we can see that we need to incorporate mph cubed in the power equation for air drag. As a simplification therefore we can say that power required is closely related to mph cubed - i.e. to double the speed of a vehicle we need 8 times the engine power. Alternatively we can express this as top speed is a function of the cube root of engine power. This means that engine modifications will have a much greater impact on acceleration (which is directly related to power) than top speed. Also that is why an old engine which is down on power might accelerate slowly but still have close to its original top speed
Roger I am curious to see your mathematical equations how you come to this conclusion since you are not calculating drag weight and distance just so I understand can you explain the formula that you're using to come to these conclusions I am extremely curious
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Power (bhp) = Total drag x mph / 375
We could if required split the power into the amounts needed to overcome each drag separately. The equations would then become:
Power to overcome rolling resistance = weight x 0.013 x mph / 375
Power to overcome air drag = fA x Cd x 0.00256 x mph cubed / 375
Hopefully something of major importance should be clear from the above. We already know that it is air resistance that is the major element in this equation and we can see that we need to incorporate mph cubed in the power equation for air drag. As a simplification therefore we can say that power required is closely related to mph cubed - i.e. to double the speed of a vehicle we need 8 times the engine power. Alternatively we can express this as top speed is a function of the cube root of engine power. This means that engine modifications will have a much greater impact on acceleration (which is directly related to power) than top speed. Also that is why an old engine which is down on power might accelerate slowly but still have close to its original top speed
Roger I am curious to see your mathematical equations how you come to this conclusion since you are not calculating drag weight and distance just so I understand can you explain the formula that you're using to come to these conclusions I am extremely curious
Sent from my iPhone

.... what I do know is my bike is now smoother and gets there quicker.