Okay according to the calculation Power = Volts x Amps
Example you need 900 watts to turn the starter @13.5 volts That = 66 amps
NOW take it that the battery has dropped to 10.5 volts the amperage is now 85 amps (as it takes the same amount of power to turn the starter i.e. 900w)
A BIG difference for a drop of 3 volts? Turning it over with a reduced charge in the battery puts a helluva current surge thru the electrics!
Not sure about your calculations. V=IR, For a given current at a given voltage you need a specific resistance, ie the starter motor. If you drop the voltage, the resistance being fixed, means the current drops not increases, as you have dropped the voltage in your calculations, by about 1/3 then the current also drops by 1/3 ie down to around 44 amps, not up to 85 amps. (using your values, as I have not measured the resistance or taken into account the back emf etc.) That's why the starter would then turns over slowly.


) and guesstimated the position on the cable for balance......fired it up and even without any more balancing (which will be completely out unless I was extremely lucky) it is running a bit better 
